LOOP STATEMENTS
=================
A PROGRAM TO PRINT NUMBERS FROM 1 TO 10

start = 1

print(start)	# 1

start = start + 1
print(start)	# 2

start = start + 1
print(start) # 3

start = start + 1
print(start)	# 4

start = start + 1
print(start)	# 5

start = start + 1
print(start)	# 6

start = start + 1
print(start)	# 7

start = start + 1
print(start)	# 8

start = start + 1
print(start)	# 9

start = start + 1
print(start)	# 10

==> there are two types of loops statements:
	1) for loop
	2) while loop
here: for and while ==> keywords 

==> for the loops, there are three things are required:
	1) initialization
	2) condition
	3) update

while loop
========
Syntax:
	initialization
	while condition:
		statement-1
		statement-2
		update

# WAP IN PYTHON TO PRINT NUMBERS FROM 1 TO 10 USING WHILE LOOP.

i = 1   # initialization

# 'i' ==> loop variable/iteration variable

while i <= 10:  # condition
    print(i)
    i = i + 1

===============================
# WAP IN PYTHON TO PRINT NUMBERS FROM 1 TO 10 USING WHILE LOOP.

i = 1   # initialization

# 'i' ==> loop variable/iteration variable

while i <= 10:  # condition
    print(i,end = "\t")
    # i = i + 1
    i += 1
====================================

# WAP IN PYTHON TO PRINT NUMBERS FROM 100 TO 1 WITH THE DIFFERENCE OF 9.

i = 100 # initialization

while i >= 1:   # condition
    print(i,end = "\t")
    i = i - 9   # update i -= 9

================================
# WAP TO FIND THE SUM OF INDIVIDUAL DIGITS OF THE GIVEN NUMBER.

"""
98765 ==> 9 + 8 + 7 + 6 + 5 ==> 35
1) DIVIDE THE TOTAL NUMBER INTO INDIVIDUAL DIGITS
IN DECIMAL NUMBER, THAT EACH DIGIT HAVE A WEIGHT(POWER)
9 x 10000 + 8 x 1000 + 7 x 100 + 6 x 10 + 5 x 1
==> 9 x 10^4 + 8 x 10^3 + 7 x 10^2 + 6 x 10^1 + 5 x 10^0
5 x 10 ==> 50
50 x 10 ==> 500
500 x 10 ==> 5000
98765 / 10
    q: 9876/10 987/10   98/10   9/10    0
    R: 5        6       7       8       9
2) ON REMAINDERS, WE SHOULD PERFORM SUM
3) PRINT THAT SUM
"""

num = int(input("Enter a value:"))  # 98765

i = num # initialization    # i = 98765
sum_dig = 0

while i > 0:
    ind_dig = i % 10    # 5 6 7 8 9
    sum_dig += ind_dig  # 5+ == 11 + 7 == 18 + 8 == 26 + 9 == 35
    i //= 10    # update 9876//10 ==> 987//10 ==> 98//10 ==> 9//10 ==> 0

print("The Sum of individual digits of",num,"is = ",sum_dig)

==============================================

# WAP TO FIND THE SUM OF ALL EVEN NUMBERS FROM 1 TO 20.

"""
we can nest with conditional statements in loop statements.
"""

i = 1
sum_evens = 0

while i <= 20:
    if i % 2 == 0:
        sum_evens += i
    i += 1

print("The sum of all even numbers = ",sum_evens)
=============================================
ASSIGNMENT:
===========
1) WAP TO FIND THE PRODUCT OF INDIVIDUAL DIGITS OF THE GIVEN NUMBER.
2) WAP TO FIND THE NUMBER OF DIGITS OF THE GIVEN NUMBER.
3) WAP IN PYTHON TO FIND THE SUM OF ALL ODD NUMBERS BETWEEN THE GIVEN RANGE.

# WAP TO CHECK WHETHER THE GIVEN NUMBER IS PALINDROME NUMBER OR NOT.

"""
PALINDROME NUMBER ==>\
NUMBER
1) FIND REVERSE NUMBER
REV_NUM = 0
REV_NUM = REV_NUM * 10 + REM

DIVISION TO TAKE INDIVIDUAL DIGITS
    NUMBER/10
        Q
        R
2) REVERSE_NUMBER == NUMBER ==> PALINDROME NUMBER

1234
REV_NUM = 4321
"""

num = int(input("Enter a value:"))  # 1221

n = num
rev_num = 0

while n != 0:
    ind_dig = n % 10    # 1 2 2 1
    rev_num = rev_num * 10 + ind_dig    # 1 X 10 + 2 == 12 X 10 + 2 ==> 122 X 10 + 1 ==> 1221
    n //= 10    # update 122//10 12//10 1//10 == 0

if rev_num == num:
    print(num,"is a palindrome number.")
else:
    print(num,"is not a palindrome number.")